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Question
Two coins are tossed simultaneously. What is the probability of getting at most one head?
Options
`1/4`
`1/2`
`2/3`
`3/4`
Solution
`3/4`
Explanation:
When two coins are tossed simultaneously, the possible outcomes are HH, HT, TH and TT.
Total number of possible outcomes = 4
Let E be the event of getting at most one head.
Then, the favourable outcomes are HT, TH and TT.
Number of favourable outcomes = 3
∴ P(getting at most 1head) = `("Number of favourable outcomes")/"Number of all possible outcomes" = 3/4`
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