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Question
Two dice are thrown simultaneously. What is the probability that:
- 4 will not come up either time?
- 4 will come up at least once?
Solution
When two dice are thrown, total possible outcomes = 36
i. Favorable outcomes for 4 will not come up either time:
{(1, 1),(1, 2),(1, 3),(1, 5),(1, 6)
(2, 1),(2, 2),(2, 3),(2, 5),(2, 6)
(3, 1),(3, 2),(3, 3),(3, 5),(3, 6)
(5, 1),(5, 2),(5, 3),(5, 5),(5, 6)
(6, 1),(6, 2),(6, 3),(6, 5),(6, 6)}
Number of favorable outcomes = 25
P(4 will not come up) = `25/36`
ii. P(4 will come up ones) = 1 – P(4 will not come up either time)
P(4 will come up once) = `1 - 25/36`
P(4 will come up once) = `(36 - 25)/36 = 11/36`
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