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Question
Two dice, one white and one red are rolled together .Find the probability of getting
(i) a sum of 6
Solution
lf two dice are rolled then the possible outcomes are :
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), ( 4, 5), ( 4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
So the total number of outcomes = 36
a sum of 6
Favorable outcomes for getting a sum 6 are:
(1, 5), (2, 4), (3, 3), (4, 2), (5, 1)
So number of favorable outcomes = 5
Thus, P(a sum of 6) = `"Number of favourable outcomes "/"Total number of outcomes"` = `5/36`
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