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Question
Two metals A and B have specific heat capacities in the ratio 2:3. If they are supplied same amount of heat then
Which metal piece will have greater mass if the rise in temperature is the same for both metals?
Solution
In this case, rise in temperature is same (Δ t) and masses are different.
So, for metal A,
Amount of heat (Q) = mA × 2 C × Δt;
and for metal B,
Amount of heat (Q) = mB × 3 C × Δt.
Now we can write, mA × 2C × Δt = mB × 3C × Δt.
Simplifying, mA = 1.5 mB.
Therefore, it can be said that metal A will have a greater mass than metal B.
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