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Question
Two numbers are in the ratio 5 : 6. If 8 is subtracted from each of the numbers, the ratio becomes 4 : 5. Find the numbers.
Solution
Let the two numbers be x and y.
By the given first condition
x : y = 5 : 6
6x = 5y ...(Product of the extreme is equal to the product of the means)
6x – 5y = 0 → (1)
Again by the given second condition
x – 8 : y – 8 = 4 : 5
5(x – 8) = 4(y – 8)
5x – 40 = 4y – 32
5x – 4y = – 32 + 40
5x – 4y = 8 → (2)
(1) × 4 ⇒ 24x – 20y = 0 → (3)
(2) × 5 ⇒ 25x – 20y = 40 → (4)
(3) – (4) ⇒ – x + 0 = – 40
∴ x = 40
Substitute the value of x = 40 in (1)
6(40) – 5y = 0
240 – 5y = 0 ⇒ – 5y = – 240
5y = 240
y = `240/5`
= 48
The two numbers are 40 and 48 ...[∴ The ratio of the number = 40 : 48 are 5 : 6]
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