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Question
Use the letters only written in the Periodic Table given below to answer the questions that Follow :
1) State the number of valence electrons in atom J.
2) Which element shown forms ions with a single negative charge?
3)Which metallic element is more reactive than R?
4) Which element has its electrons arranged in four shells?
Solution
1) 5
Atom J is a Group 5 element and a group is determined by the number of electrons present in the outermost shell.
2) Element M from Group 7 accepts one electron to form an ion with a single negative charge
3) T is more reactive than R.
The tendency of losing electrons increases down the group. Because chemical reactivity depends on the tendency to lose electrons, thus reactivity increases on going down the group.
4) Element T has its electrons arranged in four shells
Element T belongs to Period 4, and all elements of this period have four shells.
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A(4), B(9), C(14), D(19), E(20)
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Elements in the same period have equal valency
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On moving form right to left in the second period, the number of valency electrons ...............
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Column I Elements | Atomic Number | Electronic Configuration | Underline the element present in that group |
1. Hydrogen | 1 | ______ | Be/Na/Ca |
2. Carbon | 6 | ______, ______ | N/P/Si |
3. Nitrogen | 7 | _______, ______ | C/P/S |
4. Oxygen | 8 | _______, ______ | N/S/Cl |
5. Sulphur | 16 | _____, ______, _______ | O/N/F |
6. Chlorine | 17 | _____, ______, ______ | I/O/S |