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Maharashtra State BoardSSC (English Medium) 6th Standard

Vedika Has 23.50 Metres of Cloth. She Used It to Make 5 Curtains of Equal Size. If Each Curtain Required 4 Metres 25 Cm to Make, How Much Cloth is Left Over? - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

Vedika has 23.50 metres of cloth. She used it to make 5 curtains of equal size. If each curtain required 4 metres 25 cm to make, how much cloth is left over?

Sum

Solution

We know, that 1 m = 100 cm

Length of cloth required to make each curtain = 4 m 25 cm

= 4m + `25/100` m           

= 4 m + 0.25 m

= 4.25 m

Length of cloth required to make 5 curtains = Length of cloth required to make each curtain × 5

= 4.25 m × 5

= `425/100xx5/1`

= `(425xx5)/(100xx1)`

= `2125/100`

= 21.25 m

∴ Amount of cloth left = Total length of the cloth − Length of cloth required to make 5 curtains

= 23.50 m − 21.25 m

= 2.25 m

         410
    23.5 0
− 21.2 5  
     2.2 5  

Thus, the length of the cloth leftover is 2.25 m.

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Chapter 5: Decimal Fractions - Practice Set 16 [Page 34]

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Balbharati Mathematics [English] 6 Standard Maharashtra State Board
Chapter 5 Decimal Fractions
Practice Set 16 | Q 5 | Page 34
Balbharati Integrated 6 Standard Part 2 [English Medium] Maharashtra State Board
Chapter 3.1 Decimal Fractions
PRACTICE SET 16 | Q 5. | Page 46
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