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Maharashtra State BoardSSC (English Medium) 6th Standard

Veena Has Some Beads. She Wants to Make Necklaces with an Equal Number of Beads in Each. If She Makes Necklaces of 16 Or 24 Or 40 Beads, There is No Bead Left Over. - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

Veena has some beads. She wants to make necklaces with an equal number of beads in each. If she makes necklaces of 16 or 24 or 40 beads, there is no bead left over. What is the least number of beads with her?

Sum

Solution

Veena wants to make necklaces with an equal number of beads in each such there is no bead left over, so the number of beads with her must be in multiples of 16, 24, and 40. Therefore, the least number of beads with her is the LCM of 16, 24, and 40.

Multiples of 16: 16, 32, 48, 64, 80, 96, 112, 128, 144, 160, 176, 192, 208, 224, 240, 256, 272, 288,...

Multiples of 24: 24, 48, 72, 96, 120, 144, 168, 192, 216, 240, 264,...

Multiples of 40: 40, 80, 120, 160, 200, 240, 280,...

Common multiples of 16, 24, and 40: 240,...

∴ Least number of beads with Veena = LCM of 16, 24 and 40 = 240

Thus, the least number of beads with Veena is 240.

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Chapter 9: HCF-LCM - Practice Set 25 [Page 50]

APPEARS IN

Balbharati Mathematics [English] 6 Standard Maharashtra State Board
Chapter 9 HCF-LCM
Practice Set 25 | Q 2.2 | Page 50
Balbharati Integrated 6 Standard Part 2 [English Medium] Maharashtra State Board
Chapter 3.5 HCF-LCM
PRACTICE SET 25 | Q 2. (2) | Page 62
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