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Verify the Division Algorithm I.E. Dividend = Divisor × Quotient + Remainder, in Each of the Following. Also, Write the Quotient and Remainder. Dividend Divisor 4y3 + 8y + 8y2 + 7 2y2 − Y + 1 - Mathematics

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Question

Verify the division algorithm i.e. Dividend = Divisor × Quotient + Remainder, in each of the following. Also, write the quotient and remainder.

Dividend Divisor
4y3 + 8y + 8y2 + 7 2y2 − y + 1
Sum

Solution

Quotient =  2y + 5
Remainder =  11y + 2
Divisor =  2y2 -  y + 1

Divisor x Quotient + Remainder =  (2y2 - y + 1) (2y + 5) + 11y + 2

 =  4y3 +10y2 -  2y2 - 5y + 2y + 5 + 11y + 2

=  4y3 + 8y2 + 8y + 7

=  Dividend

Thus,
Divisor  x Quotient + Remainder  = Dividend
Hence verified.

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Chapter 8: Division of Algebraic Expressions - Exercise 8.4 [Page 12]

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RD Sharma Mathematics [English] Class 8
Chapter 8 Division of Algebraic Expressions
Exercise 8.4 | Q 21.6 | Page 12

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