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Question
Water can split into hydrogen and oxygen under suitable conditions. The equations representing the change is: 2H2O(I) → 2H2 (g) + O2(g)
If a given experiment results in 2500cm3 of hydrogen being produced, what volume of oxygen is liberated at the same time under the same conditions of temperature and pressure?
Solution
Given equation is: 2H2O (I) → 2H2 (g) + O2 (g)
According to Gay-Lussac's law;
2 volume of water produces 2 volume of hydrogen and 1 volume of oxygen
i.e 2 volume of water produces = 2 volume of hydrogen
= 2500cm3
2 volume of water will produce =1 volume of Oxygen
= 2500/ 2 = 1250 cm3
i.e.= 1250 cm3
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