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Question
What is the length of outer boundary of the park shown in the given figure? What will be the total cost of fencing it at the rate of Rs 20 per metre? There is a rectangular flower bed in the center of the park. Find the cost of manuring the flower bed at the rate of Rs 50 per square metre.
Solution
Length of outer boundary = Perimeter of park = Sum of all sides length
= (200 + 300 + 80 + 300 + 200 + 260) m
= 1340 m
Also, rate of fencing per metre = Rs. 20
Then, rate of fencing 1340 metre = 20 × 1340 = Rs. 26800
Now, length of rectangular flower bed = 100 m and breadth of rectangular flower bed = 80 m
∴ Area of rectangular flower bed = Length × Breadth
= 100 × 80
= 8000 sq.m
Also, rate of manuring the flower bed per square metre = Rs. 50
Then, rate of manuring the flower bed of area 8000 sq.m = 50 × 8000 = Rs. 400000
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