Advertisements
Advertisements
Question
What is the pressure exerted by 75 cm vertical column of mercury of density 13600 kgm−3 in SI units?
[Take g = 9.8 ms−2].
Solution
Vertical length of mercury column = h = 75 cm = 0.75 m
Density of mercury = p = 13600 kg m−3
Acceleration due to gravity = g = 9.8 ms−2
Pressure = P = ?
p = hpg
P = 0.75 × 13600 × 9.8
P = 99960 Pa
APPEARS IN
RELATED QUESTIONS
Calculate the equivalent height of mercury, which will exert as much pressure as 960 m of seawater of density 1040 kgm−3. The density of mercury is 13600 kgm−3.
The pressure of water on the ground floor, in a water pipe is 150000 Pa, whereas pressure on the fourth floor is 30000 Pa. Calculate the height of the fourth floor. Take g = 10 ms−2.
The pressure of water on the ground floor is 160000 Pa. Calculate the pressure on the fifth floor, at a height of 15 m.
(i) Calculate the height of a water column which will exert on its base the same
Pressure as the 70 cm column of mercury.
(ii) Will the height of the water column change if the cross-section of the water column is made wider?
What do you mean by relative density?
