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Question
Calculate the pressure exerted by 0.8 m vertical length of alcohol of density 0.80 gcnr5 in SI units.
[Take g = 10 ms−2].
Solution
Vertical length of alcohol column = h = 0.8 m
Density of alcohol = ρ = 0.80 g cm −3
ρ = `(0.80xx10^6)/10^3` kgm−3
ρ = 0.80 × 1000 kgm−3
ρ = 800 kg m−3
Pressure = P = ?
p = hpg
P = 0.8 × 800 × 10
= 6400 Pa
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