Advertisements
Advertisements
Question
What least number must be added to each of the numbers 5, 11, 19 and 37, so that they are in proportion?
Solution
Let x be the number added to 5, 11, 19, 37.
`(5 + x)/(11 + x) = (19 + x)/(37 + x)`
App. comp. and divi.
`(5 + x + 11 + x)/(5 + x - 11 - x) = (19 + x + 37 + x )/(19 + x - 37 - x)`
`(16 + 2x)/(-6) = (56 + 2x)/(-18)`
3(16 + 2x) = 56 + 2x
6x - 2x = 56 - 48
4x = 8
x = 2.
APPEARS IN
RELATED QUESTIONS
If a/b = c/d prove that each of the given ratio is equal to `sqrt((3a^2 - 10c^2)/(3b^2 - 10d^2))`
Find the value of the unknown in the following proportion :
`1/2 : "m" :: 14/9 : 4/3`
Find the mean proportion of the following :
ab3 and a3b
Determine if the following numbers are in proportion:
150, 200, 250, 300
The cost of 18 chairs is Rs 22770. How many such chairs can be bought for Rs 10120?
If 24 workers can build a wall in 15 days, how many days will 8 workers take to build a similar wall?
If a, b, c and d are in proportion, prove that: (5a + 7b) (2c – 3d) = (5c + 7d) (2a – 3b).
If a, b, c are in continued proportion, prove that: `(a + b)/(b + c) = (a^2(b - c))/(b^2(a - b)`.
Are the following statements true?
7.5 litres : 15 litres = 5 kg : 10 kg
If x : y = y : z, then x2 : y2 is ______.
