Advertisements
Advertisements
Question
What is the probability that an ordinary year has 53 Sundays?
Solution
There are 365 days, i.e. 52 weeks and one day
This one day can be any of the seven days of the week.
∴ P (Sunday) = \[\frac{1}{7}\]
We know that 52 weeks will have 52 Sundays.
Hence, required probability = P (an ordinary year with 53 Sundays) = \[\frac{1}{7}\]
APPEARS IN
RELATED QUESTIONS
What is the probability that a leap year has 53 Sundays and 53 Mondays?
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. List the eight elements in the sample space whose outcomes are all possible genders of the three children.
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children.
Write the following events as a set and find its probability:
The event that exactly one child is a girl.
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children.
Write the following events as a set and find its probability:
The event that at least two children are girls
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children.
Write the following events as a set and find its probability:
The event that no child is a girl
