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Question
What should be added to \[\left( \frac{2}{3} + \frac{3}{5} \right)\] to get\[\frac{- 2}{15}?\]
Solution
\[\text{Let x be added .} \]
\[ \therefore x + (\frac{2}{3} + \frac{3}{5}) = \frac{- 2}{15}\]
\[ \Rightarrow x + (\frac{10}{15} + \frac{9}{15}) = \frac{- 2}{15}\]
\[ \Rightarrow x + (\frac{10 + 9}{15}) = \frac{- 2}{15}\]
\[ \Rightarrow x = \frac{- 2}{15} - \frac{19}{15}\]
\[ \Rightarrow x = \frac{- 2 - 19}{15}\]
\[ \Rightarrow x = \frac{- 21}{15}\]
\[ \Rightarrow x = \frac{- 7}{5}\]
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| Paper | `5/11` |
| Aluminium cans | `5/8` |
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| Scrap | `3/4` |
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| State | Male | `bb(p/q)` form | Lowest terms |
| Andhra Pradesh | 61.6 | ||
| Assam | 57.1 | ||
| Bihar | 60.7 | ||
| Gujarat | 61.9 | ||
| Haryana | 64.1 | ||
| Himachal Pradesh | 65.1 | ||
| Karnataka | 62.4 | ||
| Kerala | 70.6 | ||
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Source: Registrar General of India (2003) SRS Based Abridged Lefe Tables. SRS Analytical Studies, Report No. 3 of 2003, New Delhi: Registrar General of India. The data are for the 1995-99 period; states subsequently divided are therefore included in their pre-partition states (Chhatisgarh in MP, Uttaranchal in UP and Jharkhand in Bihar)
