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Question
What should be the velocity of the electron so that its momentum equals that of 4000 Å wavelength photon.
Solution
λ = 4000 × 10−10 m
λ = `"h"/"p" = "h"/("m"_"e""v"_"e")`
ve = `"h"/(λ"m")`
ve = `(6.626 xx 10^-34)/(4000 xx 10^-10 xx 9.11 xx 10^-31)`
= `(6.626 xx 10^-34)/(1.6565 xx 10^-27)`
ve = 0.1818 × 104
ve = 1818 ms−1
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