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Question
A proton and an electron have the same kinetic energy. Which one has a greater de Broglie wavelength? Justify.
Solution
de-Broglie wavelength of the particle is λ = `"h"/"p" = "h"/sqrt(2"mK")`
i.e. `λ ∝ "h"/sqrt"m"`
As for me < mp,
So λe > λp
Hence wavelength of electron is greater than that of proton.
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