Question

When 2 × 10¹⁰ electrons are transferred from one conductor to another, a potential difference of 20 V appears between the conductors. Find the capacitance of the two conductors.

Answer 1

To find the capacitance of the two conductors, we use the formula:

`C = Q/V`

Given: 

• Number of electrons transferred: n = 2 × 10¹⁰
• Charge of one electron: e = 1.6 × 10⁻¹⁹ C
• Potential difference: V = 20V

Step 1: Calculate the total charge transferred

Q = n × e

Q = (2 × 10¹⁰) × (1.6 × 10⁻¹⁹)

Q = 3.2 × 10⁻⁹ C 

Step 2: Calculate the capacitance

`C = Q/V = (3.2 xx 10^(-9))/(20)`

C = 1.6 × 10⁻¹⁰ F = 160 pF

The capacitance of the two conductors is 160 pF (picofarads).