Advertisements
Advertisements
Question
When alpha particles are sent through a thin gold foil, most of them go straight through the foil, because ______.
Options
alpha particles are positively charged.
the mass of an alpha particle is more than the mass of an electron.
most of the part of an atom is empty space.
alpha particles move with high velocity.
Solution
When alpha particles are sent through a thin gold foil, most of them go straight through the foil, because most of the part of an atom is empty space.
Explanation:
When we pass the alpha particle on gold foil in Rutherford's alpha scattering experiment, there are a few observations that are recorded as:
- The majority of the particles are not deflected.
- Some of the particles are bent at tiny angles.
- Very few particles are deflected and returned by 180°.
As a result, we can deduce;
- The majority of the space in Atom is empty.
- A nucleus is a small location where a very small mass is concentrated.
- The mass of an atom is concentrated in the core nucleus, leaving the rest vacant.
- As a result, when positively charged alpha particles are delivered through metal foil, they pass straight through the foil.
APPEARS IN
RELATED QUESTIONS
In the ground state of ____________ electrons are in stable equilibrium, while in ____________ electrons always experience a net force. (Thomson’s model/Rutherford’s model)
Suppose you are given a chance to repeat the alpha-particle scattering experiment using a thin sheet of solid hydrogen in place of the gold foil. (Hydrogen is a solid at temperatures below 14 K.) What results do you expect?
In a Geiger-Marsden experiment, calculate the distance of closest approach to the nucleus of Z = 80, when a α-particle of 8Mev energy impinges on it before it comes momentarily to rest and reverses its direction.
How will the distance of closest approach be affected when the kinetic energy of the α-particle is doubles?
In a Geiger-Marsden experiment, calculate the distance of closest approach to the nucleus of Z = 75, when a α-particle of 5 MeV energy impinges on it before it comes momentarily to rest and reverses its direction.
How will the distance of closest approach be affected when the kinetic energy of the α-particle is doubles?
Answer the following question.
A charged particle q is moving in the presence of a magnetic field B which is inclined to an angle 30° with the direction of the motion of the particle. Draw the trajectory followed by the particle in the presence of the field and explain how the particle describes this path.
In Geiger-Marsden experiment prediction was that ______.
For 7.7 Mev alpha particles scattering from aluminium (Z = 13), the distance of closest approach in a bead on collision is ______.
Useful data
`1/(4 pi ∈_0) = 8.99 xx 10^9` newton m2C-2; c = 1.60 × 10-19 C; leV = 1.60 × 10-19j.
The radius of electron's second stationary orbit in Bohr's atom is R. The radius of 3rd orbit will be:-
The Bohr model for the H-atom relies on the Coulomb’s law of electrostatics. Coulomb’s law has not directly been verified for very short distances of the order of angstroms. Supposing Coulomb’s law between two opposite charge + q1, –q2 is modified to |F| = `(q_1q_2)/((4πε_0)) 1/r^2, r ≥ R_0 = (q_1q_2)/(4πε_0) 1/R_0^2 (R_0/r)^ε, r ≤ R_0` Calculate in such a case, the ground state energy of a H-atom, if ε = 0.1, R0 = 1Å.
The electron in a hydrogen atom is typically found at a distance of about 5.3 × 10−11 m from the nucleus which has a diameter of about 1.0 × 10−15 m. Assuming the hydrogen atom to be a sphere of radius 5.3 × 10−11 m, what fraction of its volume is occupied by the nucleus?