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When water is added to compound (A) of calcium, solution of compound (B) is formed. When carbon dioxide is passed into the solution, it turns milky due to the formation of compound (C). If excess of - Chemistry

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Question

When water is added to compound (A) of calcium, solution of compound (B) is formed. When carbon dioxide is passed into the solution, it turns milky due to the formation of compound (C). If excess of carbon dioxide is passed into the solution milkiness disappears due to the formation of compound (D). Identify the compounds A, B, C and D. Explain why the milkiness disappears in the last step.

Long Answer

Solution

Compound A reacts with water to form compound B. So, the compound A is calcium oxide. When water is added to calcium oxide, calcium hydroxide is formed. It is lime water. The compound gives a milky appearance which is compound C. The compound C is calcium carbonate. On passing, excess carbon dioxide milkiness disappears due to the formation of compound D. The compound is calcium hydrogen carbonate. The reactions are as follows:

\[\ce{CaO + H2O -> Ca(OH)2}\]

\[\ce{Ca(OH)2 + CO2 -> CaCO3}\]

\[\ce{Ca(OH)2 + CO2 + H2O -> Ca(HCO3)2}\]

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Some Important Compounds of Calcium
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Chapter 10: The s-block Elements - Multiple Choice Questions (Type - I) [Page 132]

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NCERT Exemplar Chemistry [English] Class 11
Chapter 10 The s-block Elements
Multiple Choice Questions (Type - I) | Q 50 | Page 132
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