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Question
Which of the following order of energies of molecular orbitals of \[\ce{N2}\] is correct?
Options
(π2py) < (σ2pz) < (π*2px) ≈ (π*2py)
(π2py) > (σ2pz) > (π*2px) ≈ (π*2py)
(π2py) < (σ2pz) > (π*2px) ≈ (π*2py)
(π2py) > (σ2pz) < (π*2px) ≈ (π*2py)
Solution
(π2py) < (σ2pz) < (π*2px) ≈ (π*2py)
Explanation:
In the molecules of boron \[\ce{(B2)}\], carbon \[\ce{C2)}\] and nitrogen \[\ce{(N2)}\] the energy of σ2pz molecular orbital is greater than the energy of π2px and π2py molecular orbital.
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