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Question
In which of the following molecules, `σ2p_z` molecular orbital is filled after `π2p_x` and `π2p_y` molecular orbitals?
Options
\[\ce{O2}\]
\[\ce{Ne2}\]
\[\ce{N2}\]
\[\ce{F2}\]
Solution
\[\ce{N2}\]
Explanation:
Molecules from hydrogen to nitrogen shows this type of electronic configuration:
`σ1s < σ^∗1s < σ2s < σ^∗2s < (π2p_x ≈ π2p_y)`, in `< σ2p_z < (π^∗2p_x ≈ π^∗2p_y) < σ^∗2p_z` which `σ2p_z` molecular orbital is filled after `π2p_x` and `π2p_x`.
So, amongst the given elements only nitrogen will show this type of electronic configuration in which `σ2p_z` molecular orbital is filled after `π2p_x` and `π2p_x`.
The electronic configuration of \[\ce{N2}\] is:
`σ1s^2, σ^∗1s^2, σ2s^2, σ^∗2s^2, π2p_x^2, π2p_y^2, σ2p_z^2`
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