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Question
Which of the following pair is expected to have the same bond order?
Options
\[\ce{O2, N2}\]
\[\ce{O^{+}2 , N^{-}2}\]
\[\ce{O^{-}2 , N^{+}2}\]
\[\ce{O^{-}2 , N^{-}2}\]
Solution
\[\ce{O^{+}2 , N^{-}2}\]
Explanation:
(i) The electronic configuration of \[\ce{O2}\] is:
`σ1s^2, σ^∗1s^2, σ2s^2, σ^∗2s^2, σ2p_z^2, π2p_x^2 ,π2p_y^2, π^∗2p_x^1, π^∗2p_y^1`
The bond order of \[\ce{O2}\] will be:
BO = `1/2[N_b - N_a]`
BO = `1/2[10 - 6]` = 2.0
The electronic configuration of \[\ce{N2}\]:
`σ1s^2, σ^∗1s^2, σ2s^2, σ^∗2s^2, π2p_x^2, π2p_y^2, σ2p_z^2`
The bond order of \[\ce{N2}\] will be:
BO = `1/2[N_b - N_a]`
BO = `1/2[10 - 4]` = 3.0
So, the bond order of \[\ce{O2, N2}\] will not be equal.
(ii) The electronic configuration of \[\ce{O^{+}2}\] is:
`σ1s^2, σ^∗1s^2, σ2s^2, σ^∗2s^2, σ2p_z^2, π2p_x^2 ,π2p_y^2, π^∗2p_x^1`
The bond order of \[\ce{O^{+}2}\] will be:
BO = `1/2[N_b - N_a]`
BO = `1/2[10 - 5]` = 2.5
The electronic configuration of \[\ce{N^{-}2}\] is:
`σ1s^2, σ^∗1s^2, σ2s^2, σ^∗2s^2, π2p_x^2, π2p_y^2, σ2p_z^2, π^∗2p_x^1`
The bond order of \[\ce{N^{-}2}\] will be:
BO = `1/2[N_b - N_a]`
BO = `1/2[10 - 5]` = 2.5
Hence, the bond order of \[\ce{O^{+}2, N^{-}2}\] will be equal.
(iii) The electronic configuration of \[\ce{O^{-}2}\] is:
`σ1s^2, σ^∗1s^2, σ2s^2, σ^∗2s^2, σ2p_z^2, π2p_x^2, π2p_y^2, π^∗2p_x^2, π^∗2p_y^1`
The bond order of `\[\ce{O^{-}2}\] will be:
BO = `1/2[N_b - N_a]`
BO = `1/2[10 - 7]` = 1.5
The electronic configuration of \[\ce{N^{+}2}\] is:
`σ1s^2, σ^∗1s^2, σ2s^2, σ^∗2s^2, π2p_x^2, π2p_y^2, σ2p_z^1`
The bond order of \[\ce{N^{+}2}\] will be:
BO = `1/2[N_b - N_a]`
BO = `1/2[9 - 4]` = 2.5
Hence, the bond order of \[\ce{O^{-}2, N^{+}2}\] will not be equal.
(iv)The electronic configuration of \[\ce{O^{-}2}\] is:
`σ1s^2, σ^∗1s^2, σ2s^2, σ^∗2s^2, σ2p_z^2, π2p_x^2, π2p_y^2, π^∗2p_x^2, π^∗2p_y^1`
The bond order of \[\ce{O^{-}2}\] will be:
BO = `1/2[N_b - N_a]`
BO = `1/2[10 - 7]` = 1.5
The electronic configuration of \[\ce{N^{-}2}\] will be:
`σ1s^2, σ^∗1s^2, σ2s^2, σ^∗2s^2, π2p_x^2, π2p_y^2, σ2p_z^2, π^∗2p_x^1`
The bond order of \[\ce{N^{-}2}\] will be:
BO = `1/2[N_b - N_a]`
BO = `1/2[10 - 5]` = 2.5
Hence, the bond order of \[\ce{O^{-}2, N^{-}2}\] will not be equal.
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What is meant by the term bond order?
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(i) \[\ce{CN-}\]
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(iii) \[\ce{O^{-}2}\]
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Species having same bond order are:
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(ii) \[\ce{O2 -> O^{+}2 + e-}\]
Match the species in Column I with the bond order in Column II.
| Column I | Column II |
| (i) \[\ce{NO}\] | (a) 1.5 |
| (ii) \[\ce{CO}\] | (b) 2.0 |
| (iii) \[\ce{O^{-}2}\] | (c) 2.5 |
| (iv) \[\ce{O2}\] | (d) 3.0 |
In which of the following pairs, the two species have identical bond order?
