Advertisements
Advertisements
Question
Which term of the AP 21, 18, 15, …… is -81?
Solution
The given AP is 21,18,15,.......
First term, a = 21
Common difference, d= 18 -21 =-3
Suppose nth term of the given AP is - 81. then,
an = -81
⇒ 21 +(n-1) × (-3) =-81 [an = a + (n-1)d]
⇒ -3 (n-1) = -81 -21=-102
⇒ `n-1 = 102/3 = 34`
⇒ n= 34+1=35
Hence, the 35th term of the given AP is -81.
APPEARS IN
RELATED QUESTIONS
If (3y – 1), (3y + 5) and (5y + 1) are three consecutive terms of an AP then find the value of y.
If ` 4/5 ` , a , 2 are in AP, find the value of a.
Fill up the boxes and find out the number of terms in the A.P.
1,3,5,....,149 .
Here a = 1 , d =b`[ ], t_n = 149`
tn = a + (n-1) d
∴ 149 =`[ ] ∴149 = 2n - [ ]`
∴ n =`[ ]`
A piece of equipment cost a certain factory Rs 60,000. If it depreciates in value, 15% the first, 13.5% the next year, 12% the third year, and so on. What will be its value at the end of 10 years, all percentages applying to the original cost?
If the sum of three consecutive terms of an increasing A.P. is 51 and the product of the first and third of these terms is 273, then the third term is
Q.4
The 11th term and the 21st term of an A.P are 16 and 29 respectively, then find the first term, common difference and the 34th term.
If Sn denotes the sum of first n terms of an AP, prove that S12 = 3(S8 – S4)
Find the sum of first 17 terms of an AP whose 4th and 9th terms are –15 and –30 respectively.
The sum of A.P. 4, 7, 10, 13, ........ upto 20 terms is ______.