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Question
Which term of the A.P. −4, −1, 2, ... is 101?
Solution
We have been given an arithmetic progression where
a = −4, d = −1− (−4) =3 and an = 101
We need to find which term of the given AP is 101 so, we need to find n.
Using an = a + (n − 1)d
Substituting the values in the formula we get
101 = −4 + (n−1)3
101+ 7 = 3n
3n =108
n =36
Therefore, 36th term of given A.P is 101.
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