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Question
While preparing for a competitive examination, Akbar came across a match-stick pattern based question. The pattern is given below:
Based on the above information, answer the following questions:
- Write first term and common difference of the AP formed by number of squares in each figure. [1]
- Write first term and common difference of the AP formed by number of sticks used in each figure. [1]
-
- How many squares are there in Fig (10)? Also, write the number of sticks used in figure. (10). [2]
OR - If 88 sticks are used to make mth (fig (m)), then find the value of m. How many squares are formed in this figure? [2]
- How many squares are there in Fig (10)? Also, write the number of sticks used in figure. (10). [2]
Solution
Given matchstick pattern:
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Number of squares | 1 | 5 | 9 |
Number of matchsticks | 4 | 16 | 28 |
(i) The AP corresponding to the number of squares in each figure is 1, 5, 9, ........
First term of AP = 1
Common difference of AP = 5 − 1 = 4
(ii) The AP corresponding to the number of sticks used in each figure is 4, 16, 28 ........
First term of AP = 4
Common difference of AP = 16 − 4 = 12
(iii)
(a) From part (i), the AP corresponding to the number of squares is 1, 5, 9, ........
Here, a = 1 and 5 − 1 = 4
We have to find a10
We know that an = a + (n − 1)d
= 1 + (10 − 1)4
= 1 + 9 × 4
= 37
Fig. (10) will have 37 squares.
From part (ii), the AP we get corresponding to the number of matchsticks used is 4, 16, 28, ........
Here, a = 4 and d = 16 − 4 = 12
We have to find a10.
We know that an = a + (n − 1)d
a10 = 4 + (10 − 1)12
= 4 + 9 × 12
= 4 + 108
= 112
∴ Fig. (10) will have 112 matchsticks.
OR
(b) We have given, am = 88
a + (m − 1)d = 88
4 + (m − 1)12 = 88 ...[∵ a = 4, d = 12]
(m − 1)12 = 84
m − 1 = 7
∴ m = 8
∴ Fig. (8) will have 88 matchsticks.
To find the number of squares in 8th figure we have to find a8 for the AP 1, 5, 9, ........
a8 = a + (8 − 1)d
a8 = 1 + 7 × 4
= 29
Therefore, 8th figure will have 29 squares.