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Why is the EoVVE(V3+/V2+)o value for vanadium comparatively low? - Chemistry

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Question

Why is the `"E"_(("V"^(3+)//"V"^(2+)))^"o"` value for vanadium comparatively low?

One Line Answer

Solution

The low value for V is related to the stability of V2+ (half-filled t2g level).

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