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Question
Solution
Slope of AB (m1) = `(6 - 8)/(-2 - 12) = (-2)/(-14) = 1/7`
Slope of BC (m2) = `(0 - 6)/(6 + 2) = (-3)/4`
Slope of AC (m3) = `(0 - 8)/(6 - 12) = (-8)/(-6) = 4/3`
Slope of BC x Slope of AC = m2 x m3
= `(-3)/4 xx 4/3`
= -1
`therefore` AC and BC are perpendicular to each other and ABC form a right angled traiangle.
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