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Question
Write balanced chemical equation for the following word equation.
Lead nitrate + Potassium iodide → Lead iodide + Potassium nitrate
Is this a double displacement reaction? Justify your answer. Name the compound precipitated and write the ions present in it.
Solution
The balanced chemical equation for the reaction between lead nitrate and potassium iodide is:
\[\ce{Pb(NO3)2(aq) + 2KI(aq)->PbI2(s) + 2KNO3(aq)}\]
This reaction is indeed a double displacement reaction, as it involves the exchange of ions between the two reacting compounds. In a double displacement reaction, the anions and cations of two different reactants switch places, forming two new compounds. Here, the nitrate ions (NO3−) from lead nitrate switch places with the iodide ions (I−) from potassium iodide, resulting in the formation of lead iodide (PbI2) and potassium nitrate (KNO3). The compound that precipitates (forms a solid) in this reaction is lead iodide (PbI2), and the ions present in it are lead ions (Pb2+) and iodide ions (I−).
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