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Question
Write the observation and name of the product for the following
(i) When ethene is passed in bromine solution in CCl4.
(ii) When Baeyer's reagent reacts with ethene.
Solution
(i) When ethene is passed in bromine solution in CCI4, the orange colour of bromine disappears due to formation of colourless ethylene bromide.
\[\ce{CH2 = CH2 + Br2 -> CH2Br - CH2Br}\]
(ii) When Baeyer's reagent reacts with ethene, colour of potassium permanganate gets discharged in this reaction.
\[\ce{CH2 = Ch2 + H2O + O ->[25°C-30°C][KMnO] Ch2OH - CH2OH}\]
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