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Question
Write the first five terms of the sequences whose nth term is:
`a_n = (2n -3)/6`
Solution
an = `(2"n" - 3)/6`
Substituting n = 1, 2, 3, 4, 5, we obtain
a1 = `(2 xx 1 - 3)/6 = (2 - 3)/6 = -1/6`,
a2 = `(2 xx 2 - 3)/6 = (4 - 3)/6 = 1/6`,
a3 = `(2 xx 3 - 3)/6 = (6 -3)/6 = 3/6 = 1/2`
a4 = `(2 xx 4 - 3)/6 = (8 - 3)/6 = 5/6`,
a5 = `(2 xx 5 - 3)/6 = (10 - 3)/6 = 7/6`
Hence, the five terms of the sequence are `-1/6, 1/6, 1/2, 5/6, 7/6`.
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