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Question
Write the following in ascending order:
`5sqrt(7), 7sqrt(5) and 6sqrt(2)`
Solution
`5sqrt(7) = sqrt(5^2 xx 7) = sqrt(25 xx 7) = sqrt(175)`
`7sqrt(5) = sqrt(7^2 xx 5) = sqrt(49 xx 5) = sqrt(245)`
`6sqrt(2) = sqrt(6^2 xx 2) = sqrt(36 xx 2) = sqrt(72)`
Since, 72 < 175 < 245, we have `sqrt(72) < sqrt(175) < sqrt(245)`.
Hence, `6sqrt(2) < 5sqrt(7) < 7sqrt(5)`.
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