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Question
Write the length of largest chord of a circle with radius 3.2 cm.
Solution 1
Radius 3.2 cm
∴ The largest chord of a circle is the diameter (D)
And D = 2 R
= 2 × 3.2
Largest chord = 6.4 cm
Solution 2
Given, Radius = 3.2 cm.
The largest chord of a circle is the diameter of that circle.
∴ Length of largest chord = diameter
= 2 × radius
= 2 × 3.2
= 6.4 cm
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RELATED QUESTIONS
In the given figure, m(arc WY) = 44°, m(arc ZX) = 68°, then
(1) Find the measure of ∠ ZTX.
(2) If WT = 4.8, TX = 8.0,
YT = 6.4, find TZ.
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Chords AB and CD of a circle intersect inside the circle at point E. If AE = 4, EB = 10, CE = 8, then find ED.
Four alternative answers for the following question are given. Choose the correct alternative and write its alphabet:
A circle having radius 3 cm, then the length of its largest chord is ______.
Given:
Chords AB and CD of a circle with centre P intersect at point E.
To prove:
AE × EB = CE × ED
Construction:
Draw seg AC and seg BD.
Fill in the blanks and complete the proof.
Proof:
In Δ CAE and Δ BDE,
∠AEC ≅ ∠DEB ...`square`
`square` ≅ ∠BDE ...(angles inscribed in the same arc)
∴ ΔCAE ~ ΔBDE ...`square`
∴ `square/ ("DE") = ("CE")/square` ...`square`
∴ AE × EB = CE × ED.
