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Question
Write the Maclaurin series expansion of the following functions:
sin x
Solution
Let f(x) = sin x
f(x) = sin x, f(0) = 0
f'(x) = cos x, f'(0) = 1
f”(x) = – sin x, f”(0) = 0
f”‘(x) = – cos x, f”'(0) = –1
fIV(x) = sin x, fIV(0) = 0
fV(x) = cos x, fV(0) = 1
fVI(x) = – sin x, fVI(0) = 0
fVII(x) = – cos x, fVII(0) = –1
Maclaurin ‘s expansion is
f(x) = `sum_("n" = 0)^oo ("f"^("n")(0)x^"n")/("n"!)`
= `"f"(0) + ("f'"(0))/(1!) x + ("f'"(0))/(2!) x^2 + ... + ("f"^("n")(0) x^"n")/("n"!) + ...`
∴ sin x = `0 + 1/(1!) x + 0 - 1/(3!) x^3 + 0 + 1/(5!) x^5 + 0 - 1/(7!) x^7 + ....`
sin x = `x/(1!) - x^3/(3!) + x^5/(5!) - x^7/(7!) + ...`
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