Advertisements
Advertisements
Question
Write the mechanism of acid catalysed dehydration of ethanol to give ethene.
Solution
Mechanism of acid catlaysed dehydration of ethanol:
Step 1: Protonation of ethanol
\[\begin{array}{cc}
\phantom{...............................}\ce{H}\\
\phantom{...............................}|\\
\ce{\underset{(Ethanol)}{CH3 - CH2 - \underset{\bullet\bullet}{\overset{\bullet\bullet}{O}}} - H ->[H - OSO3H] CH3 - CH2 - \underset{⊕}{O} - H + HS\overset{Θ}{O4}}
\end{array}\]
Step 2: Elimination of water molecule
\[\begin{array}{cc}
\ce{H}\phantom{....................}\\
|\phantom{....................}\\
\ce{CH2 - CH2 - O - H -> \underset{(Ethene)}{CH2 = CH2} + H2O + H^+}\\
|\phantom{................................................}\\
\ce{H}\phantom{................................................}
\end{array}\]
APPEARS IN
RELATED QUESTIONS
How is the conversion effected benzyl alcohol to benzoic acid?
Draw the major product formed when 1-ethoxyprop-1-ene is heated with one equivalent of HI
What will be the product (X and A) for the following reaction?
acetylchloride \[\ce{->[i) CH3MgBr][ii) H3O+] X ->[acid K2Cr2O7] A}\]
What will be the product (X and A)for the following reaction
acetylchloride \[\ce{{acetylchloride}->[i)CH3MgBr][ii)H3O+]X ->[acidK2Cr2O7] A}\]
Draw the major product formed when 1-ethoxyprop-1-ene is heated with one equivalent of HI
Draw the major product formed when 1-ethoxyprop-1-ene is heated with one equivalent of HI.
Identify the product (s) is / are formed when 1 – methoxy propane is heated with excess HI. Name the mechanism involved in the reaction.
What will be the product (X and A) for the following reaction.
\[\ce{acetylchloride ->[i) CH3MgBr][ii) H3O^+] X ->[acid K2Cr2O7] A}\]
Identify the product(s) is/are formed when 1-methoxy propane is heated with excess HI. Name the mechanism involved in the reaction.
Draw the major product formed when 1-ethoxyprop-1-ene is heated with one equivalent of HI.