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Question
Write the reaction to convert propene to n-propyl alcohol.
Solution
\[\ce{\underset{Propene}{6CH3 - CH = CH2 + (BH3)2 ->[THF]} 2(CH3CH2CH2)3 B}\]
\[\ce{(CH3 - CH2 CH2)3 B + 3H2O2 ->[NaOH] \underset{n - propyl alcohol}{3CH3CH2CH2OH} + H3BO3}\]
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