Advertisements
Advertisements
Question
`(x-1)(2x-1)=0`
Solution
`2x^2-3x+1=0`
Comparing it with `ax^2+bx+c=0` we get
`a=2, b=-3 and c=1`
∴ Discriminant `D=b^2-4ac=(-3)^2-4xx2xx1=9-8=1`
APPEARS IN
RELATED QUESTIONS
In the following, determine whether the given quadratic equation have real roots and if so, find the roots:
16x2 = 24x + 1
In the following, determine whether the given quadratic equation have real roots and if so, find the roots:
`3x^2+2sqrt5x-5=0`
In the following, determine whether the given quadratic equation have real roots and if so, find the roots:
x2 - 2x + 1 = 0
Solve for x:
`1/x - 1/(x-2)=3`, x ≠ 0, 2
`11-x=2x^2`
Find the roots of the each of the following equations, if they exist, by applying the quadratic formula:
`x^2-4x-1=0`
`4sqrt3x^2+5x-2sqrt3=0`
Find the values of k for which the given quadratic equation has real and distinct roots:
`x^2-kx+9=0`
For what value of k, are the roots of the quadratic equation kx (x − 2) + 6 = 0 equal ?
Solve for x: \[\frac{16}{x} - 1 = \frac{15}{x + 1}, x \neq 0, - 1\]