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Question
Find the values of k for which the given quadratic equation has real and distinct roots:
`x^2-kx+9=0`
Solution
The given equation is `x^2-kx+9=0`
∴`D=(-k)^2-4xx1xx9=k^2-36`
The given equation has real and distinct roots if D>0
∴`k^2-36>0`
⇒`(k-6) (k+6)>0`
⇒`k<-6 or k>6`
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