Find the Values of K for Which the Given Quadratic Equation Has Real and Distinct Roots: `Kx^2+6x+1=0` - Mathematics

Question

Find the values of k for which the given quadratic equation has real and distinct roots:

$k x^{2} + 6 x + 1 = 0$

Solution

The given equation is $k x^{2} + 6 x + 1 = 0$

∴ $D = 6^{2} - 4 \times k \times 1 = 36 - 4 k$

The given equation has real and distinct roots if D > 0.

∴ $36 - 4 k > 0$

⇒ $4 k < 36$

⇒ $k < 9$

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Relationship Between Discriminant and Nature of Roots

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Q 19.1 Q 18 Q 19.2

Chapter 10: Quadratic Equations - Exercises 4

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RS Aggarwal Mathematics [English] Class 10

Chapter 10 Quadratic Equations
Exercises 4 | Q 19.1

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Find the Values of K for Which the Given Quadratic Equation Has Real and Distinct Roots: $K x^{2} + 6 x + 1 = 0$ - Mathematics

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