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Question
`x^2-6x+3=0`
Solution
`x^2-6x+3=0`
⇒`x^2-6x=-3`
⇒`x^2-2xx x xx3+3^2=-3+3^2` (Adding `3^2` on both sides)
⇒`(x-3)^2=-3+9=6`
⇒`x-3=+-sqrt6` (Taking square root on the both sides)
⇒`x-3=sqrt6 or x-3=-sqrt6`
⇒`x=3+-sqrt6 or x=3-sqrt6`
Hence, `3+sqrt6 and 3-sqrt6` are the roots of the given equation.
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