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Question
`x^2-4x+1=0`
Solution
`x^2-4x+1=0`
⇒`x^2-4x=1`
⇒`x^2-2xx x xx2+2^2=-1+2^2` (Adding `2^2`on both sides)
⇒`(x-2)^2=+-sqrt3`
⇒`x-2=+-sqrt3` (Taking square root on the both sides)
⇒`x-2=sqrt3 or x-2=-sqrt3`
⇒`x=2+sqrt3 or x=2-sqrt3`
Hence, `2+sqrt3 and 2-sqrt3` are the roots of the given equation.
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