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Question
Solve the following quadratic equations by factorization:
`7x + 3/x=35 3/5`
Solution
We have been given,
`7x + 3/x=35 3/5`
`7x^2+3/x=(35+3/5)x`
`7x^2-(35+3/5)x+3=0`
Therefore,
`7x^2-35x-3/5x+3=0`
`7x(x-5)-3/5(x-5)=0`
`(7x-3/5)(x-5)=0`
Therefore,
`7x-3/5=0`
`7x=3/5`
`x=3/35`
or,
x - 5 = 0
x = 5
Hence, `x=3/35` or x = 5.
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