Advertisements
Advertisements
प्रश्न
Solve the following quadratic equations by factorization:
`7x + 3/x=35 3/5`
उत्तर
We have been given,
`7x + 3/x=35 3/5`
`7x^2+3/x=(35+3/5)x`
`7x^2-(35+3/5)x+3=0`
Therefore,
`7x^2-35x-3/5x+3=0`
`7x(x-5)-3/5(x-5)=0`
`(7x-3/5)(x-5)=0`
Therefore,
`7x-3/5=0`
`7x=3/5`
`x=3/35`
or,
x - 5 = 0
x = 5
Hence, `x=3/35` or x = 5.
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
`2/2^2-5/x+2=0`
Solve the following quadratic equations by factorization:
\[3\left( \frac{3x - 1}{2x + 3} \right) - 2\left( \frac{2x + 3}{3x - 1} \right) = 5; x \neq \frac{1}{3}, - \frac{3}{2}\]
Write the set of value of 'a' for which the equation x2 + ax − 1 = 0 has real roots.
If \[\left( a^2 + b^2 \right) x^2 + 2\left( ab + bd \right)x + c^2 + d^2 = 0\] has no real roots, then
If one root of the equation 4x2 − 2x + (λ − 4) = 0 be the reciprocal of the other, then λ =
A farmer wishes to grow a 100m2 rectangular vegetable garden. Since he was with him only 30m barbed wire, he fences 3 sides of the rectangular garden letting the compound of his house to act as the 4th side. Find the dimensions of his garden .
Solve equation using factorisation method:
x2 – 10x – 24 = 0
Find the factors of the Polynomial 3x2 - 2x - 1.
In each of the following determine whether the given values are solutions of the equation or not.
x2 + 6x + 5 = 0; x = -1, x = -5
A two digit positive number is such that the product of its digits is 6. If 9 is added to the number, the digits interchange their places. Find the number.
