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योग – व्यवकलन तालिका को पूरा कीजिए: - Mathematics (गणित)

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Question

योग – व्यवकलन तालिका को पूरा कीजिए:

Sum

Solution

`1/2 + 1/3`

= `[(1 xx 3) + (1 xx 2)]/6`

= `(3 + 2)/6`

= `5/6`

`1/3 + 1/4`

= `[(1 × 4) + (1 xx 3)]/12`

= `(4 + 3)/12`

= `7/12`

`1/2 - 1/3`

= `[(1 xx 3) – (1 xx 2)]/6`

= `(3 - 2)/6`

= `1/6`

`1/3 - 1/4`

= `[(1 xx 4) – (1 xx 3)]/12`

= `(4 - 3)/12`

= `1/12`

`1/6 + 1/12`

= `[(1 xx 2) + 1]/12`

= `(2 + 1)/12`

= `3/12`

= `1/4`

अतः दी गई तालिका है, 

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भिन्नों का योग
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Chapter 7: भिन्न - प्रश्नावली 7.6 [Page 175]

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NCERT Mathematics [Hindi] Class 6
Chapter 7 भिन्न
प्रश्नावली 7.6 | Q 5. (b) | Page 175
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