Aldehydes and Ketones - Preparation of Aldehydes

Write the structure of the product of the following reaction:

The reagent in friedel - craft reaction is:

Can Gatterman-Koch reaction be considered similar to Friedel Craft’s acylation? Discuss.

Ethylbenzene is generally prepared by acetylation of benzene followed by reduction and not by direct alkylation. Think of a possible reason.

In the chromyl chloride test, the final step results in the formation of a yellow precipitate of the following:

Write the name of the reaction, structure and IUPAC name of the product formed when:

CH₃CH₂CN reacts with stannous chloride in the presence of hydrochloric acid, followed by hydrolysis.

The oxidation of toluene to benzoic acid can be stopped at the aldehyde stage to give benzaldehyde. The reagent used for the purpose is one of the following.

Match the example given in Column I with the name of the reaction in Column II.

	Column I (Example)		Column II (Reaction)
(i)	$$\begin{array}{c}\phantom{...}\mathrm{O}\phantom{..............................}\mathrm{O}\phantom{}\\ \phantom{...}||\phantom{..............................}||\phantom{}\\ \mathrm{CH}{\phantom{A}}_3-\mathrm{C}-\mathrm{Cl}+\mathrm{H}{\phantom{A}}_2\stackrel{\mathrm{Pd}-\mathrm{C}/\mathrm{BasO}{\phantom{A}}_4}{\to }\mathrm{CH}{\phantom{A}}_3-\mathrm{C}-\mathrm{H}\end{array}$$	(a)	Friedel Crafts acylation
(ii)		(b)	HVZ reaction
(iii)		(c)	Aldol condensation
(iv)	$$\begin{array}{c}\mathrm{R}-\mathrm{CH}{\phantom{A}}_2-\mathrm{COOH}\stackrel{\mathrm{Br}/\mathrm{Red}\mathrm{P}}{\to }\mathrm{R}-\mathrm{CH}-\mathrm{COOH}\\ \phantom{.....................}|\\ \phantom{.......................}\mathrm{Br}\end{array}$$	(d)	Cannizaro’s reaction
(v)	$$\mathrm{CH}{\phantom{A}}_3-\mathrm{CN}\underset{(\mathrm{ii})\mathrm{H}{\phantom{A}}_2\mathrm{O}/\mathrm{H}{\phantom{A}}^{+}}{\overset{(\mathrm{i})\mathrm{SnCl}{\phantom{A}}_2/\mathrm{HCl}}{\to }}\mathrm{CH}{\phantom{A}}_3\mathrm{CHO}$$	(e)	Rosenmund’s reductio
(vi)	$$2\mathrm{CH}{\phantom{A}}_3\mathrm{CHO}\stackrel{\mathrm{NaOH}}{\to }\mathrm{CH}{\phantom{A}}_3-\mathrm{CH}=\mathrm{CHCHO}$$	(f)	Stephen’s reaction