Advertisements
Advertisements
प्रश्न
Match the example given in Column I with the name of the reaction in Column II.
| Column I (Example) |
Column II (Reaction) |
||
| (i) | \[\begin{array}{cc} \phantom{...}\ce{O}\phantom{..............................}\ce{O}\phantom{}\\ \phantom{...}||\phantom{..............................}||\phantom{}\\ \ce{CH3 - C - Cl + H2 ->[Pd - C/BasO4] CH3 - C - H} \end{array}\] |
(a) | Friedel Crafts acylation |
| (ii) |  |
(b) | HVZ reaction |
| (iii) |  |
(c) | Aldol condensation |
| (iv) | \[\begin{array}{cc} \ce{R - CH2 - COOH ->[Br/Red P] R - CH - COOH}\\ \phantom{.....................}|\\ \phantom{.......................}\ce{Br} \end{array}\] |
(d) | Cannizaro’s reaction |
| (v) | \[\ce{CH3 - CN ->[(i) SnCl2/HCl][(ii) H2O/H+] CH3CHO}\] | (e) | Rosenmund’s reductio |
| (vi) | \[\ce{2CH3CHO ->[NaOH] CH3 - CH = CHCHO}\] | (f) | Stephen’s reaction |
उत्तर
| Column I (Example) |
Column II (Reaction) |
||
| (i) | \[\begin{array}{cc} \phantom{...}\ce{O}\phantom{..............................}\ce{O}\phantom{}\\ \phantom{...}||\phantom{..............................}||\phantom{}\\ \ce{CH3 - C - Cl + H2 ->[Pd - C/BasO4] CH3 - C - H} \end{array}\] |
(e) | Rosenmund’s reductio |
| (ii) | |
(d) | Cannizaro’s reaction |
| (iii) | |
(a) | Friedel Crafts acylation |
| (iv) | \[\begin{array}{cc} \ce{R - CH2 - COOH ->[Br/Red P] R - CH - COOH}\\ \phantom{.....................}|\\ \phantom{.......................}\ce{Br} \end{array}\] |
(b) | HVZ reaction |
| (v) | \[\ce{CH3 - CN ->[(i) SnCl2/HCl][(ii) H2O/H+] CH3CHO}\] | (f) | Stephen’s reaction |
| (vi) | \[\ce{2CH3CHO ->[NaOH] CH3 - CH = CHCHO}\] | (c) | Aldol condensation |
APPEARS IN
संबंधित प्रश्न
Write the product in the following reaction:
How will you bring about the following conversion?
Benzoyl chloride to benzaldehyde
When 0.4g of oxalic acid is dissolved in 40g of benzene, the freezing point of the solution is lowered by 0.45 K. Calculate the degree of association of acetic acid. Acetic acid forms dimer when dissolved in benzene.
(Kf for benzene = 5.12 K kg mol-1, at. wt. C = 12, H = 1, O = 16)
Ozonolysis of alkenes followed by the reaction with zinc dust and water gives ____________ depending on the substitution pattern of the alkene.
Match the acids given in Column I with their correct IUPAC names given in Column II.
| Column I (Acids) |
Column II (IUPAC names) |
||
| (i) | Phthalic acid | (a) | Hexane-1,6-dioic acid |
| (ii) | Oxalic acid | (b) | Benzene-1,2-dicarboxylic acid |
| (iii) | Succinic acid | (c) | Pentane-1,5-dioic acid |
| (iv) | Adipic acid | (d) | Butane-1,4-dioic acid |
| (v) | Glutaric acid | (e) | Ethane-1,2-dioic acid |
In the chromyl chloride test, the final step results in the formation of a yellow precipitate of the following:
Convert the following:
Benzoic acid to Benzaldehyde
The reaction of benzene with CO and HCl in the presence of anhydrous AlCl3 gives ______.
Account for the following:
Reduction of nitrobenzene using Fe and HCl is preferred over Sn and HCl.
Write the name of the reaction, structure and IUPAC name of the product formed when:
CH3CH2CN reacts with stannous chloride in the presence of hydrochloric acid, followed by hydrolysis.
