Advertisements
Advertisements
प्रश्न
1032 – 1022 = ______ × (103 – 102) = ______.
रिक्त स्थान भरें
उत्तर
1032 – 1022 = (103 + 102) × (103 – 102) = 205.
Explanation:
We have,
1032 – 1022 = (103 + 102)(103 – 102) ...[∵ a2 – b2 = (a + b)(a – b)]
= 205 × 1
= 205
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Expand `("a"-1/"a")^2`
Factors of 4 – m2 are
Expand the following square, using suitable identities
(xyz – 1)2
Show that (m – n)2 + (m + n)2 = 2(m2 + n2)
Factorise the following using suitable identity
x2 – 8x + 16
The factors of x2 – 6x + 9 are
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
y2 – 14y + 49
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
`x^2/4 - 2x + 4`
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
`9y^2 - 4xy + (4x^2)/9`
Factorise the following.
y2 – 2y – 15
