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A closely wound solenoid 80 cm long has 5 layers of windings of 400 turns each. The diameter of the solenoid is 1.8 cm. If the current carried is 8.0 A, estimate the magnitude of B inside - Physics

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प्रश्न

A closely wound solenoid 80 cm long has 5 layers of windings of 400 turns each. The diameter of the solenoid is 1.8 cm. If the current carried is 8.0 A, estimate the magnitude of B inside the solenoid near its centre.

संख्यात्मक

उत्तर

Length of the solenoid, l = 80 cm = 0.8 m

There are five layers of windings of 400 turns each on the solenoid.

∴ Total number of turns on the solenoid, N = 5 × 400 = 2000

Diameter of the solenoid, D = 1.8 cm = 0.018 m

Current carried by the solenoid, I = 8.0 A

Magnitude of the magnetic field inside the solenoid near its centre is given by the relation,

B = `(mu_0"NI")/"l"`

Where,

`mu_0` = Permeability of free space

= 4π × 10–7 T m A–1

B = `(4pi xx 10^-7 xx 2000 xx 8)/(0.8)`

= 8π × 10–3

= 2.512 × 10–2 T

Hence, the magnitude of the magnetic field inside the solenoid near its centre is 2.512 × 10–2 T.

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अध्याय 4: Moving Charges and Magnetism - Exercise [पृष्ठ १६९]

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एनसीईआरटी Physics [English] Class 12
अध्याय 4 Moving Charges and Magnetism
Exercise | Q 4.8 | पृष्ठ १६९
एनसीईआरटी Physics [English] Class 12
अध्याय 4 Moving Charges and Magnetism
Exercise 2 | Q 8 | पृष्ठ १६९

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