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प्रश्न
A field is `16 1/2` m long and `12 2/5` m wide. Find the perimeter of the field.
उत्तर
Length of field = `16 1/2` m
Breadth of field = `12 2/5` m
∴ Perimeter of field = 2 (l + b)
`= 2 xx (16 1/2 + 12 2/5)`
`= 2 xx (33/2 + 62/5)`
`= 2 xx ((33 xx 5)/(2 xx 5) + (62 xx 2)/(5 xx 2))`
(∵ L.C.M. of 2 and 5 = 10)
`= 2 xx ((165 + 124)/10)`
`= 2 xx 289/10 = 289/5 "m" = 57 4/5 "m"`
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संबंधित प्रश्न
Convert given fraction into a fraction with equal denominator:
`5/6 "and" 7/9`
Find the greater fraction:
`3/5 "and" 11/15`
Insert one fraction between:
`9/17 "and" 6/13`
Insert two fractions between 1 and `3/11`
Reduce to a single fraction:
`2 1/2 + 2 1/3 - 1 1/4`
Simplify: `3/4 xx 6`
Simplify: `3/4 xx 1/2`
Simplify: `1 div 3/5`
Subtract: `-3/7 "from" 3/7`
Simplify and reduce to a simple fraction:
`(3/5)/7`
